The vapour pressure of a solution having 2.0 g of solute X (gram atomic mass=32 g/mol) in 100 g of CS2 (vapour pressure =854torr) is 848.9 torr.The molecular formula of solute 1)

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The vapour pressure of a solution having 2.0 g of solute X (gram atomic mass=32 g/mol) in 100 g of CS2 (vapour pressure =854torr) is 848.9 torr.The molecular formula of solute 1) X 2)X2 3)X4 4)X8
The vapour pressure of a solution having 2-0 g of solute X -gram atomic mass-32 g-mol- in 100 g of CS2 -vapour pressure -854torr- is 848-9 torr-The molecular formula of solute 1- X 2-X2 3-X4 4-X8

Vapour pressure of a solution of `5g`of non-electrolyte in `100g`water at a

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Stoichiometry Practice 2 answer key

our WUSS) 22. The vapour pressure of a solution having 2.0 g of solute X (gram atomic mass = 32 g mol-1) in 100 g of CS, (vapour pressure = 854 torr)

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The vapour pressure of a solution having 2.0 gram of solute X in hundred gram of CS2 is it 848.9 torr. the molecular formula of the solute is

LOPOUL 2. The vapour pressure of a solution having 2.0 g of solute X (gram atomic mass = 32 g mol-') in 100 g of CS, (vapour pressure = 854 torr) is

Solved Q1. Complete the followings: (0.5 Mark each) a) If a

The vapour pressure of CS2 50°C is 854 torr and a solution of 2.0 gm sulphur in 100 gm of CS2 has vapour pressure 848.9 torr. If the formula of sulphur molecule

⏩SOLVED:Calculate the vapor pressure at 25^∘ C of a solution…

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